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instrument implementation / implementation-contract
Buffer Preparation Calculator implementation
A source-bound implementation contract for Buffer Preparation Calculator; deployment and executable qualification remain separate.
Binding contract
This record describes what an executable surface must bind and validate. It does not claim that a public calculator, package, or production route is deployed.
- Record owner
- Guth Instruments
- Lifecycle
- verified-with-binding-errata
- Evidence ID
- t4-063
- Effect
- Computation or source lookup only
Input and validation requirements
The extreme pH input pH=-400 causes 10^-400 to underflow to zero in plain JavaScript arithmetic, silently eliminating the conjugate-base component instead of representing its mathematically nonzero amount. The convention probe also exposes a potentially catastrophic mL-versus-L interpretation error if units are not enforced.
Required corrections
[
{
"vector": 4,
"field": "volumes + moles",
"wrong": "acid 6.6667 mL, NaOH 3.3333 mL, water 90.0 mL, base_formed 0.0133333",
"correct": "acid stock 20 mL (0.02 mol total needed), NaOH 6.656 mL of 2 M (0.013312 mol, r=10^0.30=1.99526), water 73.34 mL",
"cause": "output volumes contradict her own working (which correctly says initial acid = 0.02 mol); also used 10^0.30=2 exactly"
}
]Inspectable interface fixture
The sample below is evidence for interface and validation tests, not a production implementation.
{
"inputs": {
"mode": "weak_acid_plus_conjugate_base",
"target_pH": 4.76,
"pKa": 4.76,
"total_buffer_concentration_M": 0.1,
"final_volume_L": 1,
"weak_acid": "acetic acid",
"conjugate_base": "sodium acetate, anhydrous",
"weak_acid_molar_mass_g_per_mol": 60.05,
"conjugate_base_molar_mass_g_per_mol": 82.03
},
"expected_outputs": {
"weak_acid_moles": 0.05,
"conjugate_base_moles": 0.05,
"weak_acid_mass_g": 3.0025,
"conjugate_base_mass_g": 4.1015
},
"working": "1. Ratio A⁻/HA = 10^(pH−pKa) = 10^(4.76−4.76) = 1. 2. [HA] = C_total/(1+ratio) = 0.100/(1+1) = 0.0500 M. 3. [A⁻] = 0.100−0.0500 = 0.0500 M. 4. n(HA) = 0.0500 mol/L × 1.000 L = 0.0500 mol. 5. n(A⁻) = 0.0500 mol/L × 1.000 L = 0.0500 mol. 6. m(HA) = 0.0500 mol × 60.05 g/mol = 3.0025 g. 7. m(A⁻) = 0.0500 mol × 82.03 g/mol = 4.1015 g."
}Other records
Sources and evidence
These pointers bind the page to evidence. They do not grant authority or collapse verification into deployment.
VERIFIED_LEDGER.jsonevidence-tranche4/tranche4-results.jsontranche errata record