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Free Body Diagram / Reaction Solver (2D Rigid Body)
The current ledger marks this instrument verified clean within the source-bound verification corpus.
Inspectable records
Ledger state
The current ledger marks this instrument verified clean within the source-bound verification corpus.
- Area
- Mechanical, Civil & Structural Engineering — Statics/Dynamics, Strength of Materials, Machine Design, Civil, HVAC, Vibration
- Tranche
- tranche-6
- Evidence ID
- t6-074
- Ledger rows
- 1
No ledger note is attached.
Review findings
The equilibrium method is standard and appropriate for rigid-body static analysis, but the current specification is not sufficiently precise to implement or verify universally. NEEDS_REVIEW is required because support geometry/orientation, coordinate and sign conventions, unit handling, and behavior for indeterminate or unstable systems are unspecified. The honest label correctly limits the instrument to rigid-body static equilibrium, but it should also disclose that results require a stable, statically determinate support configuration unless a separate solver is provided.
Formula and scope findings
- ΣFx=0, ΣFy=0, and ΣM=0 are the correct equilibrium equations for a 2D rigid body in static equilibrium.
- The specification does not define force-component decomposition, moment sign convention, position-reference convention, or the support constraint equations required to apply the three equilibrium equations.
- The solver must reject or explicitly report statically indeterminate, unstable, and incompatible support configurations rather than silently returning a result.
Unit assumptions
- Each test vector states a consistent force, distance, and moment unit system; force and reaction components use the stated force unit, and moments use force-distance units.
- The coordinate system is x positive to the right and y positive upward.
- Angles are measured counterclockwise from the positive x-axis.
- Positive moments are counterclockwise.
- Forces are applied at the stated coordinates relative to the global origin, with M_z=xF_y-yF_x.
- Pin supports provide Rx and Ry but no reaction moment; roller supports on a horizontal surface provide Ry only; fixed supports provide Rx, Ry, and M.
Boundary hardening
BREAK_CLAIMED · SELF_FLAGGED
The solver must reject coincident supports when the reaction calculation divides by the zero support spacing; otherwise it can produce an undefined or nonphysical reaction. Angle-sign ambiguity can also reverse the vertical reactions if the convention is not explicit.
Errata and corrections
No applied erratum is attached to this unique-name record.
Inspectable example
4 review vectors are recorded. One source-bound sample is shown below.
{
"inputs": {
"units": "kN, m, kN·m",
"coordinate_convention": "x right, y up; positive moment counterclockwise",
"supports": {
"A": {
"type": "pin",
"position_m": [
0,
0
]
},
"B": {
"type": "roller_horizontal",
"position_m": [
4,
0
]
}
},
"forces": [
{
"magnitude_kN": 10,
"angle_deg": 270,
"position_m": [
1,
0
]
},
{
"magnitude_kN": 6,
"angle_deg": 270,
"position_m": [
3,
0
]
}
],
"applied_couples": []
},
"expected_outputs": {
"A_Rx_kN": 0,
"A_Ry_kN": 9,
"B_Ry_kN": 7,
"A_M_kN_m": 0,
"B_M_kN_m": 0
},
"working": "Resolve forces: F1x=10 cos(270°)=0, F1y=10 sin(270°)=-10 kN; F2x=6 cos(270°)=0, F2y=6 sin(270°)=-6 kN. ΣFx=Ax+0+0=0, so Ax=0 kN. Take moments about A: 4By+(1)(-10)+(3)(-6)=0; 4By-10-18=0; 4By=28; By=7 kN. ΣFy=Ay+By-10-6=0; Ay+7-16=0; Ay=9 kN. Pin and roller supports have no moment reactions."
}Related workflows
No source-defined multi-instrument workflow membership is recorded.
Sources and evidence
These pointers bind the page to evidence. They do not grant authority or collapse verification into deployment.
VERIFIED_LEDGER.json · VERIFIED_CLEANevidence-tranche6/tranche6-results.jsonBOUNDARY_HAZARD_CATALOG.json