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PCB Trace Width Calculator (IPC-2221)
The current ledger marks this instrument verified clean within the source-bound verification corpus.
Inspectable records
Ledger state
The current ledger marks this instrument verified clean within the source-bound verification corpus.
- Area
- Electrical & Electronics Engineering — Circuits, Power Systems, Electronics Lab
- Tranche
- tranche-4
- Evidence ID
- t4-198
- Ledger rows
- 1
No ledger note is attached.
Review findings
The stated IPC-2221 empirical relationship and constants are valid under the mil²/A/°C unit convention, but the specification is incomplete for its claimed width output. Define the copper-weight-to-finished-thickness conversion, enforce positive temperature rise and copper thickness, and specify minimum manufacturable width. The existing honest label appropriately advises verification against fab capability and IPC-2152.
Formula and scope findings
- The IPC-2221 inverse area formula is correct only when current is in amperes, temperature rise is in degrees Celsius, and cross-sectional area is in mil² with the stated k constants.
- The specification does not provide the required width formula: width = cross-sectional area / copper thickness.
- Copper weight in ounces must be converted to an actual finished copper thickness before width can be calculated; the required conversion convention is not specified. A common nominal assumption is 1 oz = 1.378 mil, but plating and finished-copper tolerances can change this.
- The claimed width output cannot be verified uniquely until the copper-weight-to-thickness convention is defined.
Unit assumptions
- Current is in amperes.
- Allowed temperature rise is a positive temperature increment in °C; an increment in kelvins is numerically equivalent.
- The IPC-2221 constants k = 0.048 external and k = 0.024 internal assume cross-sectional area A in mil².
- Copper thickness is assumed to be 1.378 mil per nominal ounce of copper when converting copper weight to thickness.
- Width in mil is calculated as A in mil² divided by thickness in mil.
- Width in mm is converted using 1 mil = 0.0254 mm.
Boundary hardening
BREAK_CLAIMED · SELF_FLAGGED
Zero allowed temperature rise produces a zero denominator and an undefined or unbounded required area; zero current produces a mathematically zero but physically unusable trace width; and literal negative-current handling can leave the real-number domain unless current magnitude is explicitly used.
Errata and corrections
No applied erratum is attached to this unique-name record.
Inspectable example
4 review vectors are recorded. One source-bound sample is shown below.
{
"inputs": {
"current_A": 2,
"temperature_rise_C": 10,
"copper_weight_oz": 1,
"layer": "external"
},
"expected_outputs": {
"cross_section_area_mil2": 42.39,
"trace_width_mil": 30.76,
"trace_width_mm": 0.7814
},
"working": "External k = 0.048. ΔT^0.44 = 10^0.44 ≈ 2.75423. Denominator = 0.048 × 2.75423 = 0.132203. A = (2 / 0.132203)^(1/0.725) = (15.1283)^1.37931 ≈ 42.39 mil². For 1 oz copper, thickness = 1 × 1.378 = 1.378 mil. Width = 42.39 / 1.378 ≈ 30.76 mil. Width in mm = 30.76 × 0.0254 ≈ 0.7814 mm."
}Related workflows
Sources and evidence
These pointers bind the page to evidence. They do not grant authority or collapse verification into deployment.
VERIFIED_LEDGER.json · VERIFIED_CLEANevidence-tranche4/tranche4-results.jsonBOUNDARY_HAZARD_CATALOG.json