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Projectile with Air Drag (numeric)
The current ledger marks this instrument verified clean within the source-bound verification corpus.
Inspectable records
Ledger state
The current ledger marks this instrument verified clean within the source-bound verification corpus.
- Area
- Physics — Kinematics/Projectiles/Orbits, Forces/Energy/Momentum, Rotational Dynamics, Gravitation, Oscillations/Waves, Optics, E&M Fields, Relativity, Quantum, Statistical Thermo
- Tranche
- tranche-6
- Evidence ID
- t6-017
- Ledger rows
- 1
No ledger note is attached.
Review findings
The force law is standard for a simplified constant-density quadratic-drag model, but the specification is not fully deterministic or complete enough for an unconditional PASS. Add g, initial height, coordinate convention, angle units, fixed/adaptive timestep policy, RK4 state-update details, convergence/error tolerance, ground-event handling, and the exact vacuum baseline. The four vectors deliberately include zero-drag, vertical-boundary, and exact-terminal-speed cases; the terminal-speed vectors also provide closed-form checks because every RK4 stage has zero acceleration.
Formula and scope findings
- The quadratic-drag equation is standard only when v is velocity relative to still air; with wind, it must use v_relative = v - v_wind.
- The specification does not define gravitational acceleration g as an input or fixed constant. The test vectors assume g = 9.80665 m/s² unless explicitly stated otherwise; using g = 10 m/s² changes every result.
- Terminal descent speed is only sqrt(2mg/(rho Cd A)) for steady vertical descent with constant density and constant Cd; this condition should be stated.
- Range reduction versus vacuum is undefined unless the vacuum comparison uses the same g, initial height, launch state, and ground-intersection convention.
- A trajectory integrator needs an initial height and a stopping/event rule, such as the first downward crossing of y = 0. Neither is specified.
- The phrase 'throttle timestep on-device' conflicts with deterministic RK4 verification unless the actual timestep and any adaptive-step policy are exposed.
Unit assumptions
- SI units: v0 in m/s, angle in degrees, mass in kg, area in m², air density in kg/m³, dt in s, position in m, acceleration in m/s².
- The vector equation uses upward-positive coordinates, so gravity is (0,-g).
- Cd is dimensionless and constant; rho_air is constant during each simulation.
- Unless a vector states otherwise, g = 9.80665 m/s². Vectors explicitly using g = 10 m/s² are deliberate deterministic checks.
- Angles are assumed to be degrees; this must be made explicit in the implementation.
- RK4 means classical explicit fourth-order Runge-Kutta applied simultaneously to x' = vx, y' = vy, vx' = -(rho Cd A/(2m))|v|vx, and vy' = -g -(rho Cd A/(2m))|v|vy, with fixed dt.
Boundary hardening
BREAK_CLAIMED · SELF_FLAGGED
The zero-mass input makes the acceleration coefficient divide by zero and must be rejected. The zero-timestep boundary also exposes a possible validation issue, while the zero-speed range-reduction ratio is undefined as 0/0.
Errata and corrections
No applied erratum is attached to this unique-name record.
Inspectable example
4 review vectors are recorded. One source-bound sample is shown below.
{
"inputs": {
"v0": 20,
"angle_deg": 30,
"mass_kg": 1,
"Cd": 0,
"area_m2": 1,
"rho_air_kg_m3": 1.225,
"g_m_s2": 9.81,
"initial_height_m": 0,
"dt_s": 0.1,
"sample_times_s": [
0,
1,
2
],
"ground_rule": "first downward y=0 crossing"
},
"expected_outputs": {
"trajectory_samples": [
{
"t_s": 0,
"x_m": 0,
"y_m": 0,
"vx_m_s": 17.3205081,
"vy_m_s": 10
},
{
"t_s": 1,
"x_m": 17.3205081,
"y_m": 5.095,
"vx_m_s": 17.3205081,
"vy_m_s": 0.19
},
{
"t_s": 2,
"x_m": 34.6410162,
"y_m": 0.38,
"vx_m_s": 17.3205081,
"vy_m_s": -9.62
}
],
"vacuum_flight_time_s": 2.03873598,
"vacuum_range_m": 35.3119431,
"range_reduction_m": 0,
"range_reduction_fraction": 0,
"terminal_descent_speed_m_s": null
},
"working": "Cd=0 gives k=rho*Cd*A/(2m)=0, so ax=0 and ay=-9.81. Initial components: vx=20 cos(30°)=17.3205081; vy=20 sin(30°)=10. Exact constant-acceleration solution, also reproduced exactly by RK4. First RK4 step, h=0.1: vx remains 17.3205081; vy changes from 10 to 10-9.81(0.1)=9.019; x changes by 17.3205081(0.1)=1.73205081; y changes by 10(0.1)-0.5(9.81)(0.1²)=0.95095. Second step: vy=9.019-0.981=8.038; x=3.46410162; y=0.95095+[9.019(0.1)-4.905(0.1²)]=1.85295. At t=1: x=17.3205081; y=10(1)-4.905(1²)=5.095; vy=10-9.81=0.19. At t=2: x=17.3205081(2)=34.6410162; y=20-4.905(4)=0.38; vy=10-19.62=-9.62. Vacuum ground time solves 0=10t-4.905t², so t=20/9.81=2.03873598. Range=17.3205081*2.03873598=35.3119431. Since drag is zero, reduction=35.3119431-35.3119431=0."
}Related workflows
No source-defined multi-instrument workflow membership is recorded.
Sources and evidence
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VERIFIED_LEDGER.json · VERIFIED_CLEANevidence-tranche6/tranche6-results.jsonBOUNDARY_HAZARD_CATALOG.json