sampled M@1.75 · vector 4
2.9375
2.8125
own working computes 6.125-3.0625-0.25=2.8125 then field ships 2.9375instrument / verified-with-binding-errata
The current ledger marks this instrument verified with errata that must be applied at binding time.
The current ledger marks this instrument verified with errata that must be applied at binding time.
No ledger note is attached.
The governing differential equations are correct only with explicit sign conventions and distributional jump rules. The specification is not yet implementation-deterministic because it omits reaction-equilibrium details, numerical integration/step behavior, discontinuity handling, units schema, and extrema tie/one-sided conventions. Add these definitions before release.
BREAK_CLAIMED · SELF_FLAGGED
A zero-length beam with coincident supports produces a 0/0 reaction calculation and has no determinate beam solution. The instrument must reject that input; accepting it would create undefined reactions and invalid diagrams.
sampled M@1.75 · vector 4
2.9375
2.8125
own working computes 6.125-3.0625-0.25=2.8125 then field ships 2.93754 review vectors are recorded. One source-bound sample is shown below.
{
"inputs": {
"beam_length_m": 6,
"supports": [
{
"type": "pin",
"position_m": 0
},
{
"type": "roller",
"position_m": 6
}
],
"loads": [
{
"type": "point_load",
"position_m": 3,
"magnitude_kN": 12,
"direction": "downward"
}
],
"sign_convention": "sagging_M_positive",
"integration": "exact_piecewise",
"sampled_x_m": [
0,
2,
3,
"3+",
"4",
6
]
},
"expected_outputs": {
"reactions": {
"R_A_kN": 6,
"R_B_kN": 6
},
"sampled_points": [
{
"x_m": 0,
"V_kN": 6,
"M_kNm": 0
},
{
"x_m": 2,
"V_kN": 6,
"M_kNm": 12
},
{
"x_m": "3-",
"V_kN": 6,
"M_kNm": 18
},
{
"x_m": "3+",
"V_kN": -6,
"M_kNm": 18
},
{
"x_m": 4,
"V_kN": -6,
"M_kNm": 12
},
{
"x_m": 6,
"V_kN": -6,
"M_kNm": 0
}
],
"Mmax": {
"location_m": 3,
"value_kNm": 18,
"location_note": "continuous M; V changes from +6 to -6 at x=3"
}
},
"working": "Equilibrium: R_A+R_B-12=0. Taking moments about A: 6R_B-12(3)=0, so R_B=36/6=6 kN and R_A=12-6=6 kN. For 0<=x<3, w=0, so V=6 kN and M(x)=6x; M(2)=6(2)=12 kN·m and M(3-)=6(3)=18 kN·m. At x=3, the downward point load causes V(3+)=V(3-)-12=6-12=-6 kN, while M is continuous, so M(3+)=18 kN·m. For 3<x<=6, M(x)=18-6(x-3); M(4)=18-6(1)=12 kN·m and M(6)=18-6(3)=0. Since V is positive before x=3 and negative after it, Mmax=18 kN·m at x=3."
}No source-defined multi-instrument workflow membership is recorded.
These pointers bind the page to evidence. They do not grant authority or collapse verification into deployment.
VERIFIED_LEDGER.json · VERIFIED_WITH_ERRATAevidence-tranche6/tranche6-results.jsonBOUNDARY_HAZARD_CATALOG.json